How many joules does it take to destroy earth
Web20 feb. 2024 · The energy needed to destroy this thing is: 3G (10^9M)^2/ (5 (2000*9460730472580800)) 8.3636422779773*10^48 J. at 32 Billion light years, away the amount of energy would be at: 2.8926669838492*10^62J enough to destroy the largest structure. at 46 billion light years it would be around: 1.9740128188461*10^62 J. Web23 aug. 2024 · How many joules does it take to destroy a mountain? For a minimum size of a mountain to have Large Mountain level yield at minimum via: (4.184e18 Joules) / (8 Joules/cc) = 5.230e17 cm^3, or 5.230e11 m^3 destroyed. Assuming that the mountain’s height and radius are equal, the minimum values for both radius and height should be …
How many joules does it take to destroy earth
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Web3 feb. 2010 · Force unleashed. When it comes to unleashing force quickly, Bir and her colleagues investigated boxers and found they could generate up to 5,000 newtons of force with a punch, more than that ... WebFirst, we need to use the acceleration and distance to calculate the velocity on impact. g is 9.80665 m/s 2 and the distance 15.5 meters so the speed so we get the velocity on impact to be v = √ (2 · a · d) = √ (2 · 9.80665 · …
WebIn that case the gravitational binding energy (E) will be equal to. E = 3GM 2 / 5R, where G is the gravitational constant, M is the mass of the sphere, and R is its radius. The moon has a mass 7.3*10 22 kg and a radius of 1,737 km. Plugging these numbers into the equation above we get a binding energy of 1.2*10 29 J. Now this is a lot of energy. Web6 jun. 2024 · In conclusion, there is no definitive answer to the question of how many joules of electricity can kill a person. It depends on a number of factors, including the person's body size, the voltage of the electricity, and the duration of the exposure. Generally speaking, however, it is thought that a person would need to be exposed to around 10 ...
Web16 jul. 2015 · It’s a lot. The binding energy of a smaller object, like our Moon is a tidy little 1.2 x 10^29 joules. It takes about 1800 times more energy to destroy the Earth than it takes to destroy... Web25 jan. 2016 · Earth, for example, has roughly two hundred million trillion trillion joules of this binding energy – which, as you can imagine, is quite a lot. Nevertheless, this video suggests that the ...
Web9 jun. 2024 · When Manley runs the particulars of Earth through this equation, he figures out that it'd take about 2.25 x 1032 joules, or 225 million trillion trillion joules. For much …
Web20 aug. 2015 · “The gravitational self-binding energy of the Earth is roughly 10^39 ergs,” Shara said. An “erg” is a unit of measure astronomers use, equal to 10^-7 joules. Conversely, 1 Joule equals 10 ... fitness first jumpstart packfitness first in vaWeb22 jan. 2024 · (The equation assumes a uniform density of the planet under consideration, allowing for a rough estimate.) For the Earth, you need somewhere around 10^32 joules. Step 2: Find a source of … fitness first jersey classesWeb23 jul. 2024 · When Manley runs the particulars of Earth through this equation he figures out that it’d take about 2.25 x 1032 joules or 225 million trillion trillion joules. For much larger planets such as Jupiter you’re going to need about 2 x 10 36 joules which means 2 trillion trillion trillion joules of energy.Jan 12 2016 Is there a way to destroy gravity? fitness first jersey membership costWeb11 jul. 2014 · However my equation gives = 6 x 10^41 to destroy a SS and a SN in Jules is 10^44 So THAT would put a super nova at 3 exponents above destroying a SS So, I am assuming that my number of 10^28 tons, is wrong for a supernova, and it is actually more, Since you say 10^28 tons = 10^37 J , so 10^47 J should be 2.4 x 10^34 can i bring cat on train ukWebStreet level (300-15,000 Joules) (9-C) Highest muzzle energy of a .45 ACP round: 835 Joules (Street level) Highest muzzle energy/KE of a .357 Magnum round: 1,087 Joules (Street level) KE of a IMI Desert Eagle Round (Strongest Caliber): 2200 Joules/2.2 Kilojoules (Street level) can i bring cash on a planeWeb28 aug. 2024 · how much energy would it take to destroy the earth Easy! When Manley runs the particulars of Earth through this equation, he figures out that it’d take about 2.25 x 1032 joules, or 225 million trillion. about 100,000,000° CelsiusA primary type of energy from the nuclear explosion is thermal radiation. fitness first klcc